2x+x^2=0.25

Solution for 2x+x^2=0.25 equation:

2x+x^2=0.25

We move all terms to the left:

2x+x^2-(0.25)=0

We add all the numbers together, and all the variables

x^2+2x-0.25=0

a = 1; b = 2; c = -0.25;
Δ = b2-4ac
Δ = 22-4·1·(-0.25)
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{5}}{2*1}=\frac{-2-\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{5}}{2*1}=\frac{-2+\sqrt{5}}{2}
$